Documents often contain many words that are purposefully very similar to each other. For instance, you may have a document that references a series of part numbers, and the part numbers are all very similar to each other. Or you may reference a group of file names in which the base portion of the name is the same word, but each file name has a suffix that is a number, such as the following:
Widget01 Widget02 Widget03 Widget04 Widget05
If you ever have a need to increment the numbers within your document, the process can be very tedious and error-prone to do by hand. (Depending, of course, on the number of names you need to change.) This means that the task is a perfect candidate for being done by a macro.
As an example, the following VBA macro, BumpNumbers, will search for all instances of the word Widget followed immediately by a two-digit number. The number will then be incremented.
Sub BumpNumbers() Dim J As Integer Dim sFindText As String Dim sReplaceText As String Selection.Find.ClearFormatting Selection.Find.Replacement.ClearFormatting With Selection.Find .Forward = True .Wrap = wdFindContinue .Format = False .MatchCase = False .MatchWholeWord = False .MatchWildcards = False .MatchSoundsLike = False .MatchAllWordForms = False End With For J = 98 To 1 Step -1 sFindText = "Widget" & Right("00" & Trim(CStr(J)), 2) sReplaceText = "Widget" & Right("00" & Trim(CStr(J + 1)), 2) Selection.Find.Text = sFindText Selection.Find.Replacement.Text = sReplaceText Selection.Find.Execute Replace:=wdReplaceAll Next J End Sub
Obviously, this macro is tailored to a specific need—the word Widget followed by a two-digit number. If you need to modify the macro to fit your numbering needs, you can do so by changing the For ... Next loop (so it doesn't go from 98 to 1) or by changing the text being searched for (which is assigned to the sFindText variable).
Note:
WordTips is your source for cost-effective Microsoft Word training. (Microsoft Word is the most popular word processing software in the world.) This tip (814) applies to Microsoft Word 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Word (Word 2007 and later) here: Bumping Numbers in a Document.
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2016-06-13 01:24:20
Sundarasrinivasan
how to find out two digit or many more any digits in word file
2014-09-15 15:55:42
Anonymous
Answer to "Ross".
The following lines of code have been tailored to fit the task needed.
Before using the following code use Microsoft Word's "Find And Replace" feature, and in the field for finding input "v", and in the field for replacing input "v00"
Sub BumpNumbers()
Dim J As Integer
Dim sFindText As String
Dim sReplaceText As String
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
For J = 0 To 1000 Step +1
sFindText = "v" & Right("00" & Trim(CStr(J)), 2)
sReplaceText = "v" & Right("00" & Trim(CStr(J + 1)), 2)
Selection.Find.Text = sFindText
Selection.Find.Replacement.Text = sReplaceText
Selection.Find.Execute Replace:=wdReplaceAll
Next J
End Sub
2014-08-26 01:08:50
Ross
I would like to not so much bump existing numbers but put in a series of incrementing numbers in specific places in a text. For example, if I have the marker "v" scattered throughout a text I would like to add a '1' to the first one like "v 1 ", and "v 2 " at the next instance, and so forth.
An added complication - with seems to be the clincher in my experiments is that it needs to happen only within a selection of the available text in a document.
So far I have:
Sub Increment_Verse_Number()
Dim iNextVerse As Integer
Dim sReplaceText As String
iNextVerse = 1
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
With Selection
sFindText = "v "
sReplaceText = "v" + Str$(iNextVerse) + " "
iNextVerse = iNextVerse + 1
Selection.Find.Text = sFindText
Selection.Find.Replacement.Text = sReplaceText
Selection.Find.Execute Replace:=wdReplaceOne
End With
End Sub
However on the first replace the selection is removed and whatever I can do I can't get the replace value to increment!
Thanks.
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