by Allen Wyatt
(last updated April 3, 2020)
If you are writing macros, you probably do a lot of work with string variables. A common operation related to string variables is the need to replace one occurrence of characters in a string with another occurrence. For instance, consider the following string:
"This is my string of characters."
You might want to replace "of" with another word, such as "that has". The following general-purpose function can do just that, and much more:
Function RepText(sIn As String, sFind As String, sRep As String) As String Dim x As Integer x = InStr(sIn, sFind) While x > 0 sIn = Left(sIn, x - 1) & sRep & Mid(sIn, x + Len(sFind)) x = InStr(sIn, sFind) Wend RepText = sIn End Function
As an example of how to use the function, you can do the following:
sTemp = "This is my string of characters." sTemp = RepText(sTemp, "of", "that has")
When this code is executed, sTemp will contain the string "This is my string that has characters."
In my routines, I often utilize a function just like RepText to remove extra spaces (replacing a two-space string with a single-space string) or replacing multiple spaces with a tab character. How you use it, of course, is entirely up to you.
Those who have used only the latest versions of VBA may be curious as to why I would use a function such as RepText rather than the built-in Replace function. While the Replace function does essentially the same thing as RepText, its addition to the VBA arsenal is a relatively new occurrence. If your macros have even the slightest possibility of being used in older versions of Word, then using Replace runs the risk of crashing your macro—it won't be available in those versions.
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